Ask Question
10 November, 08:10

How many grams of KO2 are needed to form 8.0 g of O2?

+5
Answers (1)
  1. 10 November, 09:09
    0
    Using the atomic weights, K = 39, O=16 so KO2 = 39+32=71. So K=39/71 = 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2 = 9.76+8g=17.76.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of KO2 are needed to form 8.0 g of O2? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers