A compound consists of 17.6% of hydrogen and 82.4% nitrogen. Determine the empirical formula of the compound

17,6% + 82,6% = 100%

mass of N = 14g

mass of H = 1g

17,6% H = 17,6g H

82,4% N = 82,4g N

17,6g : 1g = 17,6 moles of H

82,4g : 14g = 5,89 moles of N

N : H = 5,89 : 17,6 ||:5,89

N : H = 1 : 2,99≈3

the empirical formula of the compound = NH₃ (ammonia)