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11 May, 06:54

A certain weak acid, ha, has a ka value of 7.1*10-7. part a calculate the percent ionization of ha in a 0.10 m solution.

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  1. 11 May, 09:03
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    Answer is: the percent ionization of weak acid is 0.266%.

    Chemical reaction: HA (aq) ⇄ H⁺ (aq) + A⁻ (aq).

    Ka (HA) = 7.1·10 ⁻⁷.

    c (HA) = 0.10 M.

    [H ⁺] = [A⁻] = x; equilibrium concentration.

    [HA] = 0.10 M - x.

    Ka = [H ⁺] · [A⁻] / [HA].

    0,00000071 = x² / 0.1 M - x.

    Solve quadratic equation: x = 0.000266 M.

    α = 0.000266 : 0.1 M · 100% = 0.266%.
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