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8 January, 22:37

Consider the rate law below.

What effect does doubling the concentration of each reactant have on the rate? The rate increases to two times the original rate. The rate increases to four times the original rate. The rate increases to six times the original rate. The rate increases to eight times the original rate.

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  1. 9 January, 00:43
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    D) The rate increases to eight times the original rate
  2. 9 January, 01:18
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    If you double the concentration of A, the rate is doubled. If you doubled the concentration of B, since the rate law has B^2, the rate is multiplied by 4. If you double both A & B's concentrations, then the rate would be multiplied by 2*4 = 8, which is the last option.
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