What is the mass of water required to prepare 250.0 g of 10.0% copper (ii) sulfate solution?

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Chemistry

Davion Koch

26 April, 19:13

What is the mass of water required to prepare 250.0 g of 10.0% copper (ii) sulfate solution?

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Francis Maddox · Answer 1

Answer is: mass of water needed for preparation of copper (II) sulfate solution is 225 grams.

mr (CuSO ₄) = 250.0 g.

ω (CuSO₄) = 10.0% : 100% = 0.1.

m (CuSO₄) = mr (CuSO₄) · ω (CuSO₄).

m (CuSO₄) = 250 g · 0.1.

m (CuSO₄) = 25 g.

m (H₂O) = mr (CuSO₄) - m (CuSO₄).

m (H₂O) = 250 g - 25 g.

m (H₂O) = 225 g.