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25 July, 20:07

How many moles of Pb (NO3) 2 are required if 8 moles of PbCI2 are produced?

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  1. 25 July, 22:25
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    PbCl₂ can be synthesized from Pb (NO₃) ₂ using various reagents. I will be using HCl as follow,

    Pb (NO₃) ₂ + 2 HCl → PbCl₂ + 2 HNO₃

    According to equation,

    1 mole of PbCl₂ is formed by = 1 mole of Pb (NO₃) ₂

    So,

    8 moles of PbCl₂ will be produced by = X moles of Pb (NO₃) ₂

    Solving for X,

    X = (8 mol * 1 mol) : 1 mol

    X = 8 mol of Pb (NO₃) ₂

    Result:

    8 mol of Pb (NO₃) ₂ are required to produce 8 moles of PbCl₂.
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