How many moles of Pb (NO3) 2 are required if 8 moles of PbCI2 are produced?

PbCl₂ can be synthesized from Pb (NO₃) ₂ using various reagents. I will be using HCl as follow,

Pb (NO₃) ₂ + 2 HCl → PbCl₂ + 2 HNO₃

According to equation,

1 mole of PbCl₂ is formed by = 1 mole of Pb (NO₃) ₂

So,

8 moles of PbCl₂ will be produced by = X moles of Pb (NO₃) ₂

Solving for X,

X = (8 mol * 1 mol) : 1 mol

X = 8 mol of Pb (NO₃) ₂

Result:

8 mol of Pb (NO₃) ₂ are required to produce 8 moles of PbCl₂.