Ask Question
22 September, 01:36

2. The electrolyte in automobile lead storage batteries is a 3.75 M sulfuric acid solution that has a density of 1.230 g/mL. Calculate the mass percent, molality, and mol fraction of the sulfuric acid.

i am so lost dont know how to get the kg of solvent,

+5
Answers (1)
  1. 22 September, 04:19
    0
    Solutions:

    1.

    Density of solution = (1.23 g / mL) • (1000 mL / 1 L)

    = 1230 g solution/L solution.

    grams of H2SO4 = (3.75 mols H2SO4) • (98.07 g H2SO4 / 1 mol)

    = 368 g H2SO4 in 1 L.

    mass percentage H2SO4 = 368 g H2SO4 / 1230 g solution) • 100

    = 29.9% H2SO4

    2. Convert Grams to moles

    = 368 g H2SO4 • (1 mol H2SO4 / 98.07 g H2SO4)

    = 3.75 mol H2SO4

    difference of total solution - total grams = 1230 g solution - 368 g H2SO4

    = 862 g H2O.

    Convert grams to kg,

    = 862 g 8 (1 kg / 1000 g)

    = 0.862 kg H2O

    Thus,

    Molality = m

    = 3.75 mol H2SO4 /.862 kg H2O

    = 4.35.

    3. = 862 g water • (1 mole / 18 g water)

    = 47.89 mol water

    mole fraction of H2SO4 = X

    = 3.75 mol H2SO4 / (3.75 moles H2SO4 + 47.89 moles water)

    = 0.726
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “2. The electrolyte in automobile lead storage batteries is a 3.75 M sulfuric acid solution that has a density of 1.230 g/mL. Calculate the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers