What coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order ch4, o2, co2, and h2o, respectively.

The balanced equation is

CH4 (g) + 2O2 (g) - > CO2 (g) + 2H20 (g)

start with the given mass of Ch4, then convert it to moles, use the stoichiometric ratio and finally convert the number of moles to grams:

mass of CO2 = 7.20x10^-3g CH4 (1mol CH4 / 16.042g) x (1mol CO2 / 1mol CH4) x (44.01g / 1mol CO2) = 0.198g

mass of H2O = 7.20x10^-3 g CH4 (1 molCH4 / 16.042g) x (2mol H2O / 1molCH4) x (18.00g / 1mol H2O) = 0.0162g

mass of O2 = 7.20x10^-3g Ch4 (1mol/16.042g) x (2 mol O2 / 1molCh4) x (32.00g/1mol O2) = 0.0287g