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31 May, 03:01

A 50.0 g gold spoon at 10.0 °c is placed in a cup of how water 95.0 °c. how much heat does the water lose to the spoon if the spoon reaches a temperature of 59.0 °c?

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  1. 31 May, 06:57
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    Heat energy is calculated by multiplying the mass, specific heat capacity of a substance by the change in temperatures. Therefore, the heat lost by water will be given by mass of water (in kg) * specific heat capacity of water * change in temperature. This heat will be equivalent to the heat gained by the spoon calculated by mass of the spoon by specific heat capacity by change in temperature. (considering that the specific heat capacity of gold is 125.6 J/kg/k)

    hence, 0.05 kg * 49 * 125.6 J/kg/k = 307.72 Joules

    therefore, heat lost by water is equivalent to 307.72 Joules
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