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11 August, 04:26

When 6 grams of zinc are dropped into excess hydrochloric acid, how many grams of zinc chloride will be produced?

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  1. 11 August, 07:34
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    Following reaction is initiated with Zn interacts with HCl;

    Zn + 2HCl → ZnCl2 + H2

    (1mol = 65.38 g) (1 mol = 136.28g)

    Thus, 1 mol of Zn generates 1 mol of ZnCl2

    Now, 6 g Zn ≡ 0.09177 mol.

    Hence, 0.09177 mol of Zn generates 0.09117 mol of ZnCl2.

    And 0.09117 mol of ZnCl2 ≡ 12.506 g

    Thus, 6 g of Zn when dropped into excess HCl, it will produce 12.506 g of ZnCl2
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