In the following reaction, how many grams of nitroglycerin c3h5 (no3) 3 will decompose to give 25 grams of co2?4c3h5 (no3) 3 (l) 12co2 (g) 6n2 (g) 10h2o (g) o2 (g)

The balanced reaction that describes the decomposition of nitroglycerin to produce carbon dioxide, nitrogen, water and oxygen is expressed: 4c3h5 (no3) 3 (l) = 12co2 (g) + 6n2 (g) + 10h2o (g) + o2 (g). Hence for every 4 moles of nitroglycerin used, 12 moles of carbon dioxide is produced. When 25 grams of CO2 is produced, we convert this to mass and multiply by 4/12 and multiply again with the molar mass of nitroglycerin. The answer is 42.99 grams nitroglycerin.