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16 May, 10:34

A 33.69 g sample of a substance is initially at 29.4 °c. after absorbing 1623 j of heat, the temperature of the substance is 110.8 °c. what is the specific heat (sh) of the substance?

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  1. 16 May, 13:20
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    Q = mcΔT

    1623 = 33.69g x c x (110.8 - 29.4)

    1623 = 2742.366 g•°C x c

    c = 0.59j/g•°C
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