Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. suppose 41. g of hexane is mixed with 150. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

The balanced chemical equation for the reaction of hexane with O₂ is given below;

2C₆H₁₄ + 19O₂ - - > 12CO₂ + 14H₂O

Stoichiometry of hexane to oxygen is 2:19

number of hexane moles - 41 g / 86.2 g/mol = 0.476 mol

number of oxygen moles - 150 g / 32 g/mol = 4.69 mol

we need to find which reagent is the limiting reactant

If hexane is the limiting reactant

2 moles of hexane reacts with - 19 mol of oxygen

therefore 0.476 mol - 19/2 x 0.476 = 4.522 mol

since 4.69 mol of oxygen is present, O₂ is in excess and hexane is the limiting reactant.

stoichiometry of hexane to water is 2:14

2 mol of hexane gives 14 mol of water

therefore 0.476 mol of hexane forms - 14/2 x 0.476 - 3.33 mol

mass of water formed - 3.33 mol x 18.0 g/mol = 59.9 g