What volume of 0.126 M HCl is needed to neutralize 2.96g of Mg (OH) 2?

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Chemistry

Esteban Berry

30 April, 10:41

What volume of 0.126 M HCl is needed to neutralize 2.96g of Mg (OH) 2?

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Molly · Answer 1

The reaction equation is Mg (OH) 2 + 2HCl = MgCl2 + H2O. The mol number of Mg (OH) 2 is 2.96/58=0.051 mol. So we need 0.051*2=0.102 mol HCl to neutralize. The volume is 0.102/0.126=0.810 L = 810 mL.