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15 April, 11:33

A gas at 29.4 kPa is cooled from a temperature of 75°C to a temperature of 25°C at constant volume. What is the new pressure of the gas?

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  1. 15 April, 14:34
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    To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant volume pressure and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

    T1/P1 = T2/P2

    P2 = T2 x P1 / T1

    P2 = 25 x 29.4 / 75

    P2 = 9.8 kPa
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