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11 January, 16:39

What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?

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  1. 11 January, 18:34
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    The volume of SO2 produced at 325k is calculated as below

    calculate the moles of SO2 produced which is calculated as follows

    write the reacting equation

    K2SO3 + 2 HCl = 2KCl + H2O + SO2

    find the moles of HCl used

    =mass/molar mass = 15g / 36.5 g/mol = 0.411 moles

    by use of mole ratio between HCl to SO2 which is 2:1 the moles of SO2 is therefore = 0.411 / 2 = 0.206 moles of SO2

    use the idea gas equation to calculate the volume SO2

    that is V=nRT/P

    where n=0.206 moles

    R (gas constant) = 0.082 L. atm / mol. k

    T=325 K

    P=1.35 atm

    V = (0.206 moles x 0.082 L. atm/mol. k x325 k) / 1.35 atm = 4.07 L of SO2
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