Whitney's lung capacity was measured as 3.3 l at a body temperature of 37 ∘c and a pressure of 746 mmhg. how many moles of oxygen is in her lungs if air contains 21% oxygen?

the ideal gas equation is PV=nRT

where P=pressure

V=Volume

n=no. of moles

R=universal gas constant

T=temperature

The universal gas constant (R) is 0.0821 L*atm/mol*K

a pressure of 746 mmhg = 0.98 atm = 1 atm (approx)

T=37 degrees Celsius = 37+273=310 K (convert it to Kelvin by adding 273)

V=0.7 L (only getting oxygen, get 21% of 3.3L)

Solution:

(1 atm) (0.7 L) = n (0.0821 L*atm/mol*K) (310 K)

0.7 L*atm=n (25.451 L*atm/mol)

n=0.0275 mole

Answer:

n=0.0275 mole of oxygen in the lungs.