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21 March, 23:22

16) How many photons are contained in a burst of yellow light (589 nm) from a sodium lamp that contains 609 kJ of energy?

A) 3.37 * 1019 photons

B) 3.06 * 1030 photons

C) 1.81 * 1024 photons

D) 4.03 * 1028 photons

E) 2.48 * 1025 photons

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  1. 22 March, 01:09
    0
    The correct answer to this question is this one:

    find the energy of one photon:

    E=h * c/λ

    divide the energy given by the energy of one photon of that wavelength

    What I've done so far is convert wave length to m and energy to j.

    E photon = h * x / wave length

    E = (6.626 x 10^-43) (3.00 x 10^8) / 587 ^ - 9 = 3.38 x 10 ^18 J

    3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj

    609 kJ / 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 16

    E = (6.626 x 10^-34) (3.00 x 10^8) / 587 ^ - 9 = 3.38 x 10 ^19 J

    3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ - 16 Kj

    609 kJ / 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is 1.81 * 10^24 photons

    3.38 x 10 ^-19 J

    should be negative

    then 3.38 x 10 ^18 J x 1kJ/1000 J

    you're converting from J to kJ ... just like meters to kilometres, you wouldn't multiply you would divide
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