A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a velocity of 16.0 meters/second

Question

Chemistry

Paityn Vaughn

26 August, 08:16

A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a velocity of 16.0 meters/second

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Hadley · Answer 1

The kinetic energy of a moving object is calculated through the equation,

KE = 0.5mv²

where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,

KE = 0.5 (55 kg) (16 m/s) ²

KE = 7,040 J

Thus, the kinetic energy of the skydiver is approximately equal to 7 kJ.