At 25°c, the vapor in equilibrium with a solution containing carbon disulfide and acetonitrile has a total pressure of 250. torr and is 85.7 mole percent carbon disulfide. what is the mole fraction of carbon disulfide in the solution? at 25°c the vapor pressure of carbon disulfide is 361 torr. assume that the solution and vapor exhibit ideal behavior.

Question

Chemistry

Guest

13 March, 03:35

At 25°c, the vapor in equilibrium with a solution containing carbon disulfide and acetonitrile has a total pressure of 250. torr and is 85.7 mole percent carbon disulfide. what is the mole fraction of carbon disulfide in the solution? at 25°c the vapor pressure of carbon disulfide is 361 torr. assume that the solution and vapor exhibit ideal behavior.

+3

Answers (1)

Know the Answer?

Skip · Answer 1

For this question, we apply the Raoult's Law. The formula is written below:

P = P*x

where

P is the partial pressure

P * is the vapor pressure of the pure solvent

x is the mole fraction

The partial pressure is solved as follows:

P = Total P*x = (250 torr) (0.857) = 214.25 torr

Hence,

214.25 = (361 torr) (x)

x = 0.593 or 59.3%