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2 November, 02:03

At stp conditions the volume of 22g of co2 is?

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  1. 2 November, 04:21
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    At STP,

    no. of mole of CO2 = Volume of CO2/22.4 in litres

    One mole of CO2 = 12 + 16X2

    = 44 g

    Therefore, no. of mole of CO2 in 22 g = 22/44 = 0.5 mole

    Therefore,

    0.5 = V/22.4

    V = 22.4 X 0.5 = 11.2 liters
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