At stp conditions the volume of 22g of co2 is?

At STP,

no. of mole of CO2 = Volume of CO2/22.4 in litres

One mole of CO2 = 12 + 16X2

= 44 g

Therefore, no. of mole of CO2 in 22 g = 22/44 = 0.5 mole

Therefore,

0.5 = V/22.4

V = 22.4 X 0.5 = 11.2 liters