Ask Question
29 December, 08:52

How many fluorine atoms are present in 5.85 g of c2f4?

+2
Answers (1)
  1. 29 December, 10:12
    0
    The molar mass of C2F4 (tetrafluoroethylene) is equal to 100 g/mol. The number of moles of C2F4 in the given amount,

    n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4

    The number of molecules per mol is calculated through the equation,

    (0.0585 mols) x (6.022 x 10^23)

    Since there are 4 F atoms each molecule then,

    (0.0585 mols) x (6.022 x 10^23) (4)

    = 1.41 x 10^23 atoms of F
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many fluorine atoms are present in 5.85 g of c2f4? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers