A 90.00 mL solution of NaCl and ethyl alcohol has 7.83 g of salt dissolved in the alcohol. Calculate the molar concentration of the solution. Remember to use significant digit rules.

The molar concentration of the solution is calculated as follows

find the moles of NaCl used to make the solution

moles = mass/molar mass

mass = 7.83 g

molar mass = 58.5 g/mol

moles = 7.83 g / 58.5 g/mol = 0.134 moles

molarity (concentration in mol/l) = number of moles/volume in liters

volume in liters = 90ml/1000 = 0.09 liters

molarity is therefore = 0.134 moles/0.09 L = 1.49 M