Ask Question
24 February, 00:52

The concentration of the alkane in a particular sample of rainwater is 0.2 ppb. assume that the density of rainwater is close to 1.00 g/ml and find the molar concentration of

+5
Answers (1)
  1. 24 February, 02:09
    0
    Ppb stands for parts per billion 10⁻⁹.

    M (C₂₀H₄₂, alkane) = 282,55 g/mol.

    V (C₂₀H₄₂) = 1000 ml = 1 dm³.

    m (C₂₀H₄₂) = 2·10⁻⁷ g.

    n (C₂₀H₄₂) = m (C₂₀H₄₂) : M (C₂₀H₄₂).

    n (C₂₀H₄₂) = 2·10⁻⁷ g : 282,55 g/mol.

    n (C₂₀H₄₂) = 7,07·10⁻¹⁰ mol.

    c (C₂₀H₄₂) = n (C₂₀H₄₂) : V (C₂₀H₄₂).

    c (C₂₀H₄₂) = 7,07·10⁻¹⁰ mol/dm³.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The concentration of the alkane in a particular sample of rainwater is 0.2 ppb. assume that the density of rainwater is close to 1.00 g/ml ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers