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3 October, 08:18

If 13.0g of CO2 gas has a volume of 0.46L at 310K, what is its pressure in millimeters of mercury?

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  1. 3 October, 10:58
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    PV = nRT - - - > p = nRT/V

    n = m/M, so: p = mRT/VM, where:

    p - pressure

    m - mass of CO2 in grams

    R - universal gas constant

    T - temperature in K

    V - volume in L

    M - molar mass of CO2 = 44 g/mol

    133.3224 Pa = 1 mm Hg

    so i think You can handle this right now.
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