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14 June, 21:42

If 65.1L of N2 (g) is needed to properly inflate an airbag, how many grams of NaN3 (s) are needed for the reaction

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  1. 15 June, 01:28
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    The equation for this reaction is as follow,

    2 NaN₂ (s) → 2 Na (s) + 3 N₂ (g)

    According to equation,

    67.2 L N₂ (3 moles) is produced by = 102 g (2 moles) NaN₂

    So,

    65.1 L N₂ will be produced by = X g of NaN₂

    Solving for X,

    X = (102 g * 65.1 L) : 67.2

    X = 98.81 g of NaN₂

    Result:

    98.81 g of NaN₂ is required to produce 65.1 L N₂ to inflate airbag.
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