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11 July, 20:14

The gas phase decomposition of phosphine at 120 °C PH3 (g) 1/4 P4 (g) + 3/2 H2 (g) is first order in PH3 with a rate constant of 1.80*10-2 s-1. If the initial concentration of PH3 is 3.16*10-2 M, the concentration of PH3 will be M after 99 s have passed

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  1. 11 July, 21:05
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    Answer: 5.32 x 10⁻³ M

    Explanation:

    1) The rate law for a first order reaction is:

    r = - d [A] / dt = k[A]

    2) When you integrate you get:

    [ A] = Ao x e ^ (-kt)

    Remember that here A is PH₃

    3) Plug in the dа ta: Ao = 0.0316M, k = 0.0180 / s, and t = 99s

    [PH₃] = 0.0316 M x e ^ ( - 0.0180/s x 99s) = 5.32 x 10⁻³ M
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