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27 October, 21:29

How many moles of MgCl2 are there in 340 g of the compound?

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  1. 28 October, 01:01
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    To calculate the amount of the compound in the units of grams, we need to first obtain for the molar mass of the compound. We calculate as follows:

    MgCl2 = 24.31 + (2 x 35.45) = 95.21 g/mol

    340 g MgCl2 (1 mol / 95.21 g) = 3.57 mol MgCl2

    Hope this answers the question. Have a nice day.
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