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26 April, 06:39

What is the ph of 2.34 * 10^-5 naoh solution?

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  1. 26 April, 10:05
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    NaOH = Na⁺ + OH⁻

    pOH = - log [ OH⁻ ]

    pOH = - log [ 2.34x10⁻⁵ ]

    pOH = 4.63

    Therefore:

    pH + pOH = 14

    pH + 4.63 = 14

    pH = 14 - 4.63

    pH = 9.37
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