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27 April, 17:39

Phosphorus is obtained primarily from ores containing calcium phosphate. If a particular ore contains 35.1% calcium phosphate, what minimum mass of the ore must be processed to obtain 4.13 kg of phosphorus?

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  1. 27 April, 18:18
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    First, we determine the mass of calcium phosphate that is required. This is obtained by calculating the mass percentage of phosphorus in calcium phosphate, Ca₃ (PO₄) ₂

    % Phosphorus = Mass of P x 100 / total mass

    % Phosphorus = (31 * 2 * 100) / (310)

    % P = 20%

    The amount of calcium phosphate needed will be:

    4.13 / 0.2 = 20.65 kg

    Now, the ore has 35.1% calcium phosphate, so:

    Mass of ore = mass of calcium phosphate required / percentage calcium phosphate

    Mass of ore = 20.65 / 0.351

    Mass of ore = 58.83 kg
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