Identify the spectator ion in this reaction. highlight your answer. ba (oh) 2 (aq) + h2so4 (aq) → baso4 (s) + h2o (l) ba2 + so42 - oh - h + there is no spectator ion.

Question

Chemistry

Ally Gordon

3 November, 20:32

Identify the spectator ion in this reaction. highlight your answer. ba (oh) 2 (aq) + h2so4 (aq) → baso4 (s) + h2o (l) ba2 + so42 - oh - h + there is no spectator ion.

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Answers (1)

Know the Answer?

Nathen Weaver · Answer 1

Answer is: there is no spectator ion.

Balanced reaction hemical reaction:

Ba (OH) ₂ (aq) + H₂SO₄ (aq) → BaSO₄ (s) + 2H₂O (l).

Net ionic reaction:

Ba ²⁺ (aq) + 2OH⁻ (aq) + 2H⁺ (aq) + SO₄²⁻ (aq) → BaSO₄ (s) + 2H₂O (l).

Barium cation and sulfate anion form precipate and hydrogen cations and hydroxide anion form molecular water. A spectator ion is an ion that exists as a reactant and a product in a chemical equation