The mass of amu of 710 iron atoms

The atomic mass unit of 710 Fe atoms would be equal to 41125 amu. We calculate this by first dividing with the avogadro's number which is 6.022x10^23. We obtain the number of moles, then we multiply with the molar mass to obtain grams. Lastly, divide with 1.6x10^-24 to obtain amu.