Calculate the molarity of each aqueous solution: (a) 25.5 ml of 6.25 m hcl diluted to 0.500 l with water (b) 8.25 ml of 2.00*10-2 m ki diluted to 12.0 ml with water

1. Using the dilution equation;

M1V1=M2V2

M1 = 6.25 m, v1 = 25.5 ml or 0.0255 liters

Therefore; (6.25 * 0.0255) = M (0.5)

M = 0.159375/0.5

Therefore Molarity is 0.31875 M Hcl

2. From the same equation

M1v1=m2v2

m1 = 0.02 m, v1=8.25 ml or 0.00825 l, while v2 = 0.012 l

Thus, 0.02 * 0.00825 = M (0.012)

M = 0.000165/0.012

= 0.01375 m

Thus molarity is 0.01375 M KI