An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a solution is 1.05. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution.

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Chemistry

Kimberly Vaughan

8 March, 15:38

An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a solution is 1.05. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution.

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Santos Vang · Answer 1

Answer is: the volume percentage of ethylene glycol in the solution is 43.1%.

V (solution) = 1 m ³.

d (solution) = 1050 kg/m³.

m (solution) = 1050 kg.

d (ethylene glycol) = 1116 kg/m³.

d (water) = 1000 kg/m³.

m (solution) = d (ethylene glycol) · V (ethylene glycol) + d (water) · V (water).

V (ethylene glycol) = 1m³ - V (water).

1050 kg = 1116 kg/m³ · (1m³ - V (water)) + 1000 kg/m³ · V (water).

1050 kg = 1116 kg - 1116·V (water) + 1000·V (water).

116 kg/m³ ·V (water) = 66kg.

V (water) = 0.569 m³.

V (ethylene glycol) = 1 m³ - 0.569 m³ = 0.431 m³.

percentage = 0.431 m³ : 1 m³ · 100% = 43.1%.