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10 May, 09:59

How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?

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  1. 10 May, 12:25
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    The heat of fusion of 1 mole of water is 6.01 kJ/mol

    1 mole of water is equal to 18 g

    Therefore; 54,0 g of water is equivalent to 54/18 = 3 moles of water

    Hence heat required;

    = 3 * 6.01 = 18.03 kJ
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