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11 December, 13:06

Use the periodic table in the tools bar to answer these questions. How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

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  1. 11 December, 14:25
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    M = moles de soluto / litros de solucion

    moles de soluto = M. litros de solucion

    Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3
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