MnO2 + 4 HCl → Cl2 + MnCl2 + 2 H2O
Given 145.7 grams of MnO2, how much hydrochloric acid (HCl) is needed to use up the MnO2 completely (MM in g/mol: MnO2=86.94, HCl = 36.46, Cl2=70.9, MnCl2=125.84, H2O=18.02) ?
244.4 g
10.55 g
145.5 g
1407 g
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