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4 April, 15:52

A compound has a percent composition of 40.0% carbon, 6.72% hydrogen, and 53.28% oxygen. If it's molar mass is 180 g/mol, what is its molecular formula?

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  1. 4 April, 16:13
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    1) Molar composition

    Base: 100 g

    C: 40.00 g / 12.0 g / mol = 3.333 mol

    H: 6.72 g / 1 g/mol = 6.72 mol

    O: 53.28 g / 16g/mol = 3.33 mol

    2) Divide by the smaller number of moles

    C: 3.333 / 3.33 = 1.00

    H: 6.72 / 3.33 = 2.02 ≈ 2

    O: 3.33/3.33 = 1.00

    3) Empirical formula

    CH2O

    molar mass of the empirical formula = 12 g/mol + 2*1g/mol + 16 g/mol = 30 g/, ol

    4) Number of times that the mass of empirical formula is contained in the molar mass = 180 g/mol / 30 g/mol = 6

    5) Molecular formula = 6 times the empirical formula

    =>C6H12O6

    Answer: C6H12O6
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