Determine the density of nh3 gas at 435k and 1.00atm

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Chemistry

Jason Lutz

21 June, 20:01

Determine the density of nh3 gas at 435k and 1.00atm

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Evan Rush · Answer 1

We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV = nRT

P/RT = n/V where n = m/MM

P (MM) / RT = m/V = density

Density = 1.00 (17.03) / 0.08206 (435)

Density = 0.48 g / L