For the reaction:

6Li (s) + N2 (g) →2Li3N (s)

Determine:

the mass of N2 needed to react with 0.536 moles of Li.

the number of moles of Li required to make 46.4 g of Li3N.

the mass in grams of Li3N produced from 3.65 g Li.

the number of moles of lithium needed to react with 7.00 grams of N2.

Question

Chemistry

Rebecca Wall

4 March, 17:24

For the reaction:

6Li (s) + N2 (g) →2Li3N (s)

Determine:

the mass of N2 needed to react with 0.536 moles of Li.

the number of moles of Li required to make 46.4 g of Li3N.

the mass in grams of Li3N produced from 3.65 g Li.

the number of moles of lithium needed to react with 7.00 grams of N2.

+3

Answers (1)

Know the Answer?

Jimmy Gardner · Answer 1

The balanced equation represents the reaction ratio, using the unit mol. So when knowing the gram formula mass of these three molecules, we can easily known the answer. First is 2.50 g. Second: 6.61 mol. Third: 3.65 g. Forth: 1.5 mol.

For the reaction:6Li (s) + N2 (g) →2Li3N (s)Determine:the mass of N2 needed to react with 0.536 moles of Li.the number of moles of Li required to make 46.4 g of Li3N.the mass in grams of Li3N produced from 3.65 g Li.the number of moles of lithium needed to react with 7.00 grams of N2.

For the reaction:

6Li (s) + N2 (g) →2Li3N (s)

Determine:

the mass of N2 needed to react with 0.536 moles of Li.

the number of moles of Li required to make 46.4 g of Li3N.

the mass in grams of Li3N produced from 3.65 g Li.

the number of moles of lithium needed to react with 7.00 grams of N2.