MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If. 86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

Question

Chemistry

Gaige Pollard

8 September, 23:29

MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If. 86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

+1

Answers (1)

Know the Answer?

Heaven Chavez · Answer 1

HCl:

m=48,2g

M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol : 4mol

MnO ₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O

0,86mol : 1,32mol

limiting reagent

0,33 will react

HCl is limiting reagent.