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8 January, 23:19

Determine the number of moles of N atoms in 46.5g of Mg (NO3) 2

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  1. 8 January, 23:58
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    First, we determine the moles of Mg (NO₃) ₂ present:

    moles = mass / Mr

    = 46.5 / (24 + 2 x (14 + 16 x 3))

    = 0.4 mole

    Each mole of Mg (NO₃) ₂ contains 2 moles of Nitrogen atoms.

    Moles Nitrogen = 0.4 x 2

    = 0.8 mole
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