Ask Question
7 December, 19:45

The compound pcl5 decomposes into cl2 and pcl3. the equilibrium of pcl5 (g) cl2 (g) pcl3 (g) has a keq of 2.24 x 10-2 at 327°c. what is the equilibrium concentration of cl2 in a 1.00 liter vessel containing 0.235 mole of pcl5 and 0.174 mole of pcl3? remember to use the correct number of significant digits

+1
Answers (1)
  1. 7 December, 22:17
    0
    The equilibrium constant for this problem is Kp = [cl2] [pcl3]/[Pcl5]. Kp equal to 2.24 x 10-2 is given, while the initial concentration of pcl5 is 0.235 M and that of pcl3 is 0.174 M. The equation now becomes 2.24x10-2 = (0.174+x) x / (0.235-x) where x is the concentration produced from rxn and that of cl2. The equilib concentration of cl2 is then 0.22 M.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The compound pcl5 decomposes into cl2 and pcl3. the equilibrium of pcl5 (g) cl2 (g) pcl3 (g) has a keq of 2.24 x 10-2 at 327°c. what is the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers