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12 July, 07:27

What volume of 2.5% (m/v) koh can be prepared from 125 ml of a 5.0% (m/v) koh solution?

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  1. 12 July, 08:47
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    the volume of 2.5% m/v koh which can prepared from 125 ml of a 5% koh solution is calculated using the following formula

    m1v1 = m2 v2

    M1 = 5/100 = 0.05

    v1 = 125

    m2=2.5/100=0.025

    V2=?

    v2 = m1v1/m2

    =0.05 x125 / 0.025=250 ml
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