G the ksp of calcium hydroxide, ca (oh) 2, is 5.02 * 10-6. calculate the molar solubility of this compound.

When calcium hydroxide dissolves, it dissociates into Ca (OH) 2 = Ca2 + and 2OH - Let's assign the variable X for the solubility of Ca2 + and OH I. e Ca2 + = X and 2OH - = 2X Then Ksp = [Ca2+][OH-]^2 So we have (X) (2X) ^2 = 5.02 * 10^ (-6) 4X^3 = 5.02 * 10 ^ (-6) X^3 = 5.02 * 10^ (-6) / 4 X^3 = 0.003110 X = 0.1459