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31 December, 15:53

At 25 °c, only 0.0100 mol of the generic salt ab2 is soluble in 1.00 l of water. what is the ksp of the salt at 25 °c? ab2 (s) ↽--⇀a2 + (aq) + 2b - (aq)

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  1. 31 December, 19:39
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    Where the solubility product Ksp is applied where salts don't fully dissolve in a solvent.

    and when the reaction equation is:

    AB2 (s) ↔ A2 + (Aq) + 2 B - (aq)

    so we have the Ksp expression = [A2+][B-]^2

    when we assume [A2+] = X = 0.01 M

    and [B-] = 2X = 2*0.01 M = 0.02 M

    So by substitution:

    Ksp = 0.01 * (0.02) ^2

    = 4 x 10^-6
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