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Yesterday, 19:11

What is the [h3o + ] in a 0.050 m solution of ba (oh) 2?

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Answers (2)
  1. Yesterday, 19:28
    0
    The H3O + in a 0.050M solution of Ba (OH) 2 is calculated as below

    write the equation for the dissociation of Ba (OH) 2

    Ba (OH) 2 = Ba^2 + + 2OH^-

    calculate the OH - concentration

    by use of mole ratio between Ba (OH) 2 to OH^ - which is 1:2 the concentration of OH = 0.050 x2 = 0.1 M

    by use of the formula (H3O+) (OH-) = 1 x10 ^-14

    by making H3O + the subject of the formula

    H3O + = 1 x10^-14 / OH-

    substitute for OH-

    H3O + = (1 x10^-14) / 0.1

    = 1 x10^-3 M
  2. Yesterday, 22:30
    0
    Answer is: concentration of hydronium ions are 10⁻¹³ M.

    Chemical dissociation of barium hydroxide in water:

    Ba (OH) ₂ (aq) → Ba²⁺ (aq) + 2OH⁻ (aq).

    c (Ba (OH) ₂) = 0.050 M.

    From chemical reaction: n (Ba (OH) ₂) : n (OH⁻) = 1 : 2.

    c (OH ⁻) = 0.10 M = 10⁻¹ M.

    c (OH ⁻) · c (H₃O⁺) = 1·10⁻¹⁴ M².

    c (H₃O⁺) = 10⁻¹⁴ M² : 10⁻¹ M.

    c (H₃O⁺) = 10⁻¹³ M.
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