What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?

Question

Chemistry

Mariana

21 November, 17:00

What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?

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Answers (1)

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Jenna · Answer 1

Answer is: mass of sodium hydroxide is 60 grams.

V (NaOH) = 300 mL · 1 L/1000mL = 0,3 L.

c (NaOH) = 5 M = 5 mol/L.

n (NaOH) = c (NaOH) · V (NaOH).

n (NaOH) = 5 mol/L · 0,3 L.

n (NaOH) = 1,5 mol.

m (NaOH) = n (NaOH) · M (NaOH).

m (NaOH) = 1,5 mol · 40 g/mol.

m (NaOH) = 60 g.