How many grams of carbon are present in 45.0 g of CCl4?

To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 (1 mol CCl4 / 153.82 g CCl4) (1 mol C / 1 mol CCl4) (12.01 g C / 1 mol C) = 3.5135 g carbon present

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