How many mL of stomach acid (assume it is. 035 M HCI) can be neutralized by an antacid tablet containing. 231g

Mg (OH) 2?

Mg (OH) 2 (aq.) + 2HCl (aq.) - - > MgCl2 (aq.) + 2H2O (l)

n (HCl) / n (Mg (OH) 2) = 2/1

n (HCl) = 2*n (Mg (OH) 2)

c = n/V; n = c*V

n = m/M

c (HCl) * V (HCl) = 2*m (Mg (OH) 2) / M (Mg (OH) 2)

V (HCl) = 2*m (Mg (OH) 2) / (M (Mg (OH) 2) * c (HCl)) = 2 * 0,231 g / (58,326 g mole^-1 * 0,035 mole dm^-3) = 0,226 dm^3 = 226 cm^3 (cm^3 = mL)